1.

If the 9" term of an A.P.bezero, then the ratio of its 29" and 19" termis​

Answer»

Step-by-step explanation:

t9=a+8d

a+8d=0....(1)

t19=a+18d

i.e. t19=a+8d+10d

from eq(1)

t19=0+10d=10d...(2)

t29=a+28d

t29=a+8d+20d

from eq(1)

t29=0+20d=20d...(3)

t19/t29=10d/20d...frome eqs(2) and (3)

t19:t29=1:2

The ratio of t19 and t29 is 1:2 .



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