Saved Bookmarks
| 1. |
If the 6-digit number 479xyz is exactly divisible by 7, 11 and 13, then the product of the digits x, y and z will be:1. 10012. 7943. 2524. 479 |
|
Answer» Correct Answer - Option 3 : 252 Given: Six digit number is 479xyz Divisible by 7, 11, and 13. Concept Used: Any number is divisible by 7, 11, and 13 If the number is in the form of xyzxyz (repeating form) Calculation: 479xyz = 479479 ⇒ x = 4, y = 7, and z = 9 ⇒ x × y × z = 4 × 7 × 9 ⇒ x × y × z = 252 ∴ The product of xyz is 252. |
|