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If tanx=b/a where a and b are real numbers find the value of sin2a |
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Answer» SIN(2a) = 2 Tan(x) / 1+ Tan² (x) Tan² ( x ) = (b/a)² Sin(2a) = 2 ( b/a) / 1 +( b²/a²) Sin(2a) = 2 AB / (a² + b²) .......Have a NICE DAY....... |
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