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If tanθ = 3, then what is the value of (5 sinθ - 3 cosθ/ 4sinθ + 3cosθ) ? |
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Answer» ANSWER:iven, 5tanθ=3 ∴tanθ= 5 3
Now, 4sinθ+3cosθ 5sinθ−3cosθ
= 4tanθ+3 5tanθ−3 [dividing numerators and DENOMINATOR by cosθ] = 4( 5 3 )+3 5( 5 3 )−3
= 5 12 +3 3−3
= 5 12 +3 0
=0 ∴ 4sinθ+3cosθ 5sinθ−3cosθ =0
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