1.

If tanα=1√x(x2+x+1),tanβ=√x√x2+x+1and tanγ=√x−3+x−2+x−1, where x≠0, then α+β is

Answer»

If tanα=1√x(x2+x+1),tanβ=√x√x2+x+1

and tanγ=√x−3+x−2+x−1, where x≠0, then α+β is



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