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If tan Thita =12/13 find the value of. 2sin Thita cos Thita /cos2thita -sin2thita |
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Answer» TAN ●=12/13 P=12 B=13 H= ROOT 12^2+13^2 =root 144+169 =root 313 2sin●cos●/cos^2 ●-sin^2 ● see the IMAGE |
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