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If tan alpha = 2/5 , find the numerical value of (sin alpha - 2cos alpha)/(cos alpha - 3sin alpha) |
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Answer» Step-by-step EXPLANATION: We have, 5 TAN α⇒tanα= 5 4
Now, 5sinα+2cosα 5sinα−3cosα
= cosα 5sinα+2cosα
cosα 5sinα−3cosα
= cosα 5sinα
+ cosα 2cosα
cosα 5sinα
− cosα 3cosα
= 5TAN,α+2 5tan,α−3
= 5× 5 4
+2 5× 5 4
−3
= 4+2 4−3
= 6 1
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