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If tan A + cot A=4, Then prove that Tan^4 A + cot^4 A=194No spam answer please

Answer»

Given Equation is TANA + COTA = 4.


On SQUARING both SIDES, we get


= > (tanA + cotA)^2 = (4)^2


= > tan^2A + cot^2A + 2tanAcotA = 16


= > tan^2A + cot^2A + 2 * tanA * (1/tanA) = 16


= > tan^2A + cot^2A + 2 = 16


= > tan^2A + cot^2A = 16 - 2


= > tan^2A + cot^2A = 14.


On squaring both sides, we get


= > (tan^2A + cot^2A)^2 = (14)^2


= > tan^4A + cot^4A + 2 * tan^4A * cot^4a = 196


= > tan^4A + cot^4A + 2 * tan^4A * (1/tan^4A) = 196


= > tan^4A + cot^4A + 2 = 196


= > tan^4A + cot^4A = 196 - 2


= > tan^4A + cot^4A = 194.



Hope this helps!



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