1.

If tan (A+B) = √3 and tan (A-B) = 1/√3, where A and B are acute angles.Please Solve this. ​

Answer»

Answer:

tan(A+B)=√3

tan (A+B)=60--------- 1

tan (A-B) =1/√3

tan (A-B)= 30---------- 2

by compairing

adding equation 1 and 2

tan(A+B)=60

tan(A-B)=30

------------------

2A = 90

A= 45

put A in eq 1

A+B=60

45+ B =60

B =60-45

B= 15


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