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If tan 0 = 3, then what is the value of5 sin 8- 3 cose4 sin + 3 cos? |
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Answer» Answer: 5tanθ=3 ∴tanθ= 5 3
Now, 4sinθ+3cosθ 5sinθ−3cosθ
= 4tanθ+3 5tanθ−3
[dividing numerators and DENOMINATOR by cosθ] = 4( 5 3
)+3 5( 5 3
)−3
= 5 12
+3 3−3
= 5 12
+3 0
=0 ∴ 4sinθ+3cosθ 5sinθ−3cosθ
=0 Step-by-step explanation: |
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