1.

If tan 0 = 3, then what is the value of5 sin 8- 3 cose4 sin + 3 cos?​

Answer»

Answer:

5tanθ=3

∴tanθ=

5

3

Now,

4sinθ+3cosθ

5sinθ−3cosθ

=

4tanθ+3

5tanθ−3

[dividing numerators and DENOMINATOR by cosθ]

=

4(

5

3

)+3

5(

5

3

)−3

=

5

12

+3

3−3

=

5

12

+3

0

=0

∴

4sinθ+3cosθ

5sinθ−3cosθ

=0

Step-by-step explanation:

please MARK BRILLIANT



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