If t2+t+1=0, then (t+1t)2+(t2+1t2)2+(t3+1t3)2....+(t27+1t27)2 is equal – InterviewSolution

1.	If t2+t+1=0, then (t+1t)2+(t2+1t2)2+(t3+1t3)2....+(t27+1t27)2 is equal to
Answer» If $t^{2} + t + 1 = 0$ , then ${(t + \frac{1}{t})}^{2} + {(t^{2} + \frac{1}{t^{2}})}^{2} + {(t^{3} + \frac{1}{t^{3}})}^{2} . . . . + {(t^{27} + \frac{1}{t^{27}})}^{2}$ is equal to

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