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If `sum_(r=1)^(n) r(r+1) = ((n+a)(n+b)(n+c))/(3)`, where `a gt b gt c`, thenA. `2b = c`B. `a^(3)-8b^(3)+c^(3) = 8abc`C. a is prime numberD. `(a-2b)^(2) = 0` |
| Answer» Correct Answer - A | |