Saved Bookmarks
| 1. |
If sum of 'n' terms of an A.P . is 3n2+5n and am=164 , then m= |
|
Answer» ONG>Answer: Sn=3n2+5n S1=a1=3(1)2+5(1)=8 S2=3(2)2+5(2)=22 S2=22=a1+a2 a2=22-8=14 d=a2-a1=14-8=6 nth TERM value is 164,then what is N? nth term=a+(n-1)d 164=8+(n-1)6 164-8 / 6=n-1 156/6=n-1 26+1=n n=27 So 27thterm is 164. |
|