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If `sintheta=(1)/(3)`, then `costheta` will beA. `(8)/(9)`B. `(4)/(3)`C. `(2sqrt2)/(3)`D. `(3)/(4)` |
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Answer» Correct Answer - C `costheta=sqrt(1-sin^2theta)=sqrt(1-(1)/(9))=(2sqrt2)/(3)` |
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