If sinθ+cosθ=12, then 16(sin(2θ)+cos(4θ)+sin(6θ)) is equal to

1.	If sinθ+cosθ=12, then 16(sin(2θ)+cos(4θ)+sin(6θ)) is equal to
Answer» If $sin θ + cos θ = \frac{1}{2}$ , then $16 (sin (2 θ) + cos (4 θ) + sin (6 θ))$ is equal to

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