If sinA + sin²A=1and acos¹²A+bcos⁸A+ccos⁶A-1=0find value of b+c

1.	If sinA + sin²A=1and acos¹²A+bcos⁸A+ccos⁶A-1=0find value of b+c/a+b
Answer» sinA + sin²A=1 acos¹²A+bcos⁸A+ccos⁶A-1=0 find value of b+C/a+b (b + c)/(a + b) = (-2 (sqrt(5) - 2) a - sqrt(5) b + 3 b + 2 sqrt(5) + 4)/(2 (a + b)), (b + c)/(a + b) = (2 (2 + sqrt(5)) a + (3 + sqrt(5)) b - 2 sqrt(5) + 4)/(2 (a + b))

If sinA + sin²A=1and acos¹²A+bcos⁸A+ccos⁶A-1=0find value of b+c/a+b

Answer»

sinA + sin²A=1

acos¹²A+bcos⁸A+ccos⁶A-1=0

find value of b+C/a+b

(b + c)/(a + b) = (-2 (sqrt(5) - 2) a - sqrt(5) b + 3 b + 2 sqrt(5) + 4)/(2 (a + b)), (b + c)/(a + b) = (2 (2 + sqrt(5)) a + (3 + sqrt(5)) b - 2 sqrt(5) + 4)/(2 (a + b))

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If sinA + sin²A=1and acos¹²A+bcos⁸A+ccos⁶A-1=0find value of b+c/a+b​

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If sinA + sin²A=1and acos¹²A+bcos⁸A+ccos⁶A-1=0find value of b+c/a+b