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If SinA + CosA = 1/✓2, then find the value of 4SinA.CosA |
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Answer» =(sinA+cosA)²=(1/√2)² =sin²A+cos²A + 2sinAcosA= 1/2 =2sinAcosA= 1/2-1 =2(2sinAcosA)=(-1/2)2 =4sinAcosA=-1
HENCE THE VALUE OF 4SINA.COSA IS -1. |
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