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:If sinA=4/5 find the value of tan 2A and sin3A |
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Answer» Answer: Given, sinA= 5 3
= h p
∴b= 25−9
= 16
=4 secA= b h
= 4 5
, TANA= b p
= 4 3
Therefore, sec 2 A−tan 2 A=( 4 5
) 2 −( 4 3
) 2
= 16 25
− 16 9
= 16 16
=1 |
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