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If SinA=4/5 find the value of Sin2A and Cos2A |
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Answer» Sin A = 4/5 Cos A = 3/5 [ You can CHECK it by Pythagoras theorm ] Sin 2A = 2sinAcosA = 2 × 4/5 × 3/5 = 24/25 Cos 2A = cos^2 A - Sin^2 A = (3/5) ^2 - (4/5)^2 = 9/25 + 16/25 = 25/25 = 1
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