1.

If sinA=3/5, find the value of cosA-sinA/2cotA​

Answer»

ong>Step-by-step explanation:P>

SINA = 3/5 = perpendicular/hypotenuse

  • Perpendicular = 3
  • Hypotenuse = 5

Base = √(H² - P²) = √(25 - 9) = √16 = 4

Now we have

h = 5 , b = 4 , p = 3

  • sin A = p/h = 3/5
  • cos A = b/h = 4/5
  • cot A = b/p = 4/3

=> (cosA - sinA)/2cotA

=> (4/5 - 3/5) / 2*4/3

=> 1/5 × 3/8

=> 3/40


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