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If sinA=12/13 then find secA-tanA/cosA+cotA |
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Answer» Step-by-step explanation: SINA = 12/13 = p/h p= 12units h= 13units by pythagoras theorem b^2= h^2-p^2 b^2= 13^2-12^2 = 169 -144 = 25 b =ROOT of 25 b = 5 secA = 13/5 tanA= 12/5 cosA=5/13 cotA= 5/12 secA-tanA/cosA+cotA =13/5-12/5 / 5/13+5/12 =1/5 / 60/156 +65/156 =1/5 / 125/156 = 156/625 |
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