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If sinA=1/3 then find CosA CosecA+tanA secA |
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Answer» AnswEr:- We know,
So , Perpendicular = 1 and Hypotenuse = 3.
→ H² = B² + P²
=> 3² = B² + 1²
=> √8 or 2√2 = B And we know,
→ Cos A = 2√2/3
→ Sec A = 3/2√2
→ Cosec A = 3
→ Tan A = 1/2√2
→ Cos A Cosec A + Tan A Sec A
→ 2√2/3 × 3 + (1/2√2 × 3/2√2)
→ 2√2 + 3/8
→ (16√2 + 3)/8
Hence, (16√2 + 3)/8 ______________________________ |
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