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. If sin x = 20/29 find cosx |
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Answer» N, sin \thetaθ = \frac{20}{29} 29 20
= \frac{B}{c} c b
\implies a=\sqrt{c^{2}-b^{2}}⟹a= c 2 −b 2
\implies\sqrt{29^{2}-20^{2}}⟹ 29 2 −20 2
\implies\sqrt{441}⟹ 441
\implies 21⟹21 Now, cos \thetaθ = \frac{a}{c} c a
= \frac{21}{29} 29 21... |
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