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If sin inverse a + sin inverse b + sing inverse g = 3pi/4 then ab +ag+ bg is equal to? |
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Answer» Answer: 1/4-1/2(a^2+B^2+c^2) Step-by-step explanation: = 3pi/4 SIN INVERSE a + sin inverse b + sing inverse G sin{sin inverse a + sin inverse b + sing inverse g}=sin 3pie/4 a+b+g=1/√2 (a+b+g)^2=(1/√2)^2 a^2+b^2+ g^2+2(ab+bg+ag)=1/2 2ab+bg+ag=1/2-(a^2+b^2+ g^2) ab+bg+ag=1/4-1/2(a^2+b^2+g^2) |
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