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If sin A+sin²A=1 then cos²A + cos ^4A=​

Answer»

GIVEN:

sin A+sin²A=1

To find:

cos²A + COS ^4A= ?

we know cos²A+sin²A=1

⇒cos²A=1-sin²A---------(1)

ACCORDING to the problem,

sinA+sin²A=1

⇒sinA=1-sin²A--------(2)

By COMPARING both equations,

we get, sinA = cos²A

so,,,,, cos²A+cos⁴A = sinA+sin²A = 1



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