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If sin A+sin²A=1 then cos²A + cos ^4A= |
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Answer» sin A+sin²A=1 To find: cos²A + COS ^4A= ? we know cos²A+sin²A=1 ⇒cos²A=1-sin²A---------(1) ACCORDING to the problem, sinA+sin²A=1 ⇒sinA=1-sin²A--------(2) By COMPARING both equations, we get, sinA = cos²A so,,,,, cos²A+cos⁴A = sinA+sin²A = 1 |
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