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If sin(A + B) = sin A cos B + cos A sin B and cos(A - B) = cos A cos B + sin A sin B, find the values of sin 75°. |
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Answer» Given: sin (A + B) = sin A cos B + cos A sin B and cos (A – B) = cos A cos B + sin A sin B To find: sin 75° Put A = 30° and B = 45°, then sin 75° = sin 30° cos 45° + cos 30° sin 45° = (1/2) × (1/√2) + (√3/2) × (1/√2) = (1/2√2) + (√3/2√2) = (1+√3)/2√2 |
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