If sin A and cos A are roots of the equation px? +qx+m=0, then the rel

1.	If sin A and cos A are roots of the equation px? +qx+m=0, then the relation among p q and mis(A) q?+m=(p+m)?(B) q? - m2 = (p+ m)?(C) q? + m² = (p=m)?(D) of these
Answer» If sin A and cos A are roots of the equation px^2 + qx + m = 0 sinA + cosA = - q/p....... (1) sinA.cosA = m/p............(2) Squaring both sides of eq(1) (sinA + cosA)^2 = sin^2 A + cos^2 A + 2sinA.cosA (-q/p)^2 = 1 + 2*m/p q^2 = p^2 + 2mp q^2 + m^2 = p^2 + 2mp + m^2 q^2 + m^2 = (p + m)^2 (A) is correct option

If sin A and cos A are roots of the equation px? +qx+m=0, then the relation among p q and mis(A) q?+m=(p+m)?(B) q? - m2 = (p+ m)?(C) q? + m² = (p=m)?(D) of these

Answer»

If sin A and cos A are roots of the equation px^2 + qx + m = 0

sinA + cosA = - q/p....... (1)

sinA.cosA = m/p............(2)

Squaring both sides of eq(1)

(sinA + cosA)^2 = sin^2 A + cos^2 A + 2sinA.cosA

(-q/p)^2 = 1 + 2*m/p

q^2 = p^2 + 2mp

q^2 + m^2 = p^2 + 2mp + m^2

q^2 + m^2 = (p + m)^2

(A) is correct option