If sin∅ =5/13 then finda) cos∅ (b) tan∅ (c) cosec ∅ (d) tan �

1.	If sin∅ =5/13 then finda) cos∅ (b) tan∅ (c) cosec ∅ (d) tan ∅ + 1/cos∅
Answer» ong>ANSWER: sin theta=p/h = 5/13 b2=h2-p2 =169-25 =144 =12 (a)cos theta=12/13 (B)TAN theta=5/12 (C)COSEC theta=13/5 (d)tan theta +1/cos theta= 5/12+13/12=18/12

If sin∅ =5/13 then finda) cos∅ (b) tan∅ (c) cosec ∅ (d) tan ∅ + 1/cos∅

Answer»

ong>ANSWER:

sin theta=p/h = 5/13

b2=h2-p2

=169-25

=144

=12

(a)cos theta=12/13

(B)TAN theta=5/12

(C)COSEC theta=13/5

(d)tan theta +1/cos theta= 5/12+13/12=18/12

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If sin∅ =5/13 then finda) cos∅ (b) tan∅ (c) cosec ∅ (d) tan ∅ + 1/cos∅​

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If sin∅ =5/13 then finda) cos∅ (b) tan∅ (c) cosec ∅ (d) tan ∅ + 1/cos∅