1.

If sin 3A=cos (A-2°) where 3A and (A-2°) are both acute angle then A=?

Answer»

Heya mate, Here is UR answer

We KNOW that Sin THETA = Cos (90-theta)

So,

Sin 3A = Cos (A-2)

Cos (90-3A) =Cos (A-2)

90-3A=A-2

90+2=A+3A

92=4A

92/4=A

23=A

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Warm regards

@Laughterqueen

Be BRAINLY ✌✌


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