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If sin 3A = cos(A – 26°), where 3A is an acute angle, find the value of A. |
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Answer» sin 3A = cos (A-26°) …(i) We know that Sin θ = cos (90° - θ) So, Eq. (i) become Cos (90° - 3A) = cos (A -26°) On Equating both the sides, we get 90° - 3A = A – 26° ⇒ -3A - A = -26° -90° ⇒ -4A = -116° ⇒ A = 29° |
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