If sin−1x+sin−1y+sin−1z=π2, then the value of x2+y2+z2+2xyz is – InterviewSolution

1.	If sin−1x+sin−1y+sin−1z=π2, then the value of x2+y2+z2+2xyz is equal to
Answer» If ${sin}^{- 1} x + {sin}^{- 1} y + {sin}^{- 1} z = \frac{π}{2},$ then the value of $x^{2} + y^{2} + z^{2} + 2 x y z$ is equal to

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