If sin-1x + sin-1y + sin-1z = π, then prove that x√1 - x2+ y√1 - y2+ z√1 - z2= 2xyz

If sin-1x + sin-1y + sin-1z = π, then prove that x√1 - x2+ y√1 -

1.	If sin-1x + sin-1y + sin-1z = π, then prove that x√1 - x2+ y√1 - y2+ z√1 - z2= 2xyz
Answer» If sin^-1x + sin^-1y + sin^-1z = π, then prove that x√1 - x²+ y√1 - y²+ z√1 - z²= 2xyz Solution: