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If ∫sin−1√x√1−xdx=2[√x−√1−x f(x)]+C(C is integration constant), then the value of f(0) is equal to |
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Answer» If ∫sin−1√x√1−xdx=2[√x−√1−x f(x)]+C (C is integration constant), then the value of f(0) is equal to |
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