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If `sin^-1(sin 5)gtx^(2)-4x` thenA. `x in 2+sqrt(9-2pi , oo)`B. `x in 2-sqrt(9-2pi),2+sqrt(9-2pi)`C. `xin 2-sqrt(9-2pi)oo)`D. none of these |
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Answer» We have `sin^(-1)(sin5)gtx^(2)-4x` `rarr sin^(-1)sin(5-2pi)gtx^(2)-4x` `rarr 5-2 pi gt x^(2)-4x` `rarr x^(2)-4x-5+2pilt0 rarr -sqrt(9-2pi)ltxlt2+sqrt(9-2pi)` |
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