1.

If Seco-tan 0 =2 then sin 0=?​

Answer»

sec \: theta - tan \: theta = 2 \\  =  >  \frac{1}{cos \: theta}  -  \frac{sin \: theta}{cos \: theta}  = 2 \\  =  >  \frac{1 - sin \: theta}{cos \: theta}  = 2 \\  =  > sin \: theta = 1 - 2cos \: theta

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