1.

If secA=3/4 calculate the value of sinA and cosA​

Answer» ONG>ANSWER:

SECA= 3/4=H/B

B=4;H=3

P=

\sqrt{3 { }^{2} } - 4{}^{2} = \sqrt{} 9 - 16= - \sqrt { 7}

P=√-7

sinA= P/H= √-7/3

cosA=4/3


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