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If secA(1 + sinA) (1 – sin A) = k, then find the value of k. |
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Answer» ong>ANSWER: SECA(1 + sinA) (1 – sin A) = k => secA(1-sin²A) = k | (a+b)(a - b) = a²-b² Therefore, secA×cos²A = k | 1+sin²A = cos²A Therefore, 1/cosA × cos²A = k | secA = 1/cosA Therefore, cosA = k |
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