If sec θ + tan θ = x, then sec θ =(a) x2+1x(b) x2+12x(c) x2-12x(d) x2-1x

If sec θ + tan θ = x, then sec θ =(a) x2+1x(b) x2+12x(c) x2-12x(d)

1.	If sec θ + tan θ = x, then sec θ =(a) x2+1x(b) x2+12x(c) x2-12x(d) x2-1x
Answer» If sec θ + tan θ = x, then sec θ = (a) $\frac{x^{2} + 1}{x}$ (b) $\frac{x^{2} + 1}{2 x}$ (c) $\frac{x^{2} - 1}{2 x}$ (d) $\frac{x^{2} - 1}{x}$