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If sec teta=13/5 then show that 2sinteta-3costeta/4sinteta-9costeta |
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Answer» so COS x =5/13 SIN^2 x =1-cos^2 x .sin x=12/13 so 2 sin x-3 cos x/4sin x-9 cos x ⇒2x12/13-3x5/13 / 4x12/13-9x5/13 ⇒3 Answer |
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