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If sec A = cosec(A - 36°) and 5A is an acute angle, show that A = 21°. |
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Answer» Given: sec5 A = cosec(A - 36°) => cosec(90° − 5A) = cosecA − 36° ) [∵ cosec(90° − θ) = sec θ] => 90° − 5A = A − 36° => 6A = 90° + 36° => 6A = 126° => A = 21° |
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