1.

If same amount of electricity is passed through aqueous solutions of AgNO_(3) and CuSO_(4) and the number of Ag and Cu atoms deposited are'x' and 'y' respectively . Then

Answer»

`x = y`
`x LT y`
`y = 2x`
`x = 2y`

Solution :`AG^(+) + e^(-) to Ag , Cu^(2+) + 2 e^(-) to Cu` .
THUS , same quantity of ELECTRICITY will deposit double the no. of Ag ATOMS than Cu, i.e., x = 2y .


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