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If S is circumcentre, O is orthocentre of `DeltaABC`, then `vec(SA)+vec(SB)+vec(SC)`=A. `vec(SO)`B. `2vec(SO)`C. `vec(OS)`D. `2vec(OS)` |
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Answer» Correct Answer - B `az^(3)+bz^(2)+bar(b)z+bar(a)=0impliesbar(a)bar(z)^(3)+bar(b) bar(z)^(2)+b bar(z)+a=0impliesz=(1)/(z)" "thereforezbar(z)=1implies|z|=1` |
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