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If resistance `R_1` in resistance box is `300 Omega` then the balanced length is found to be `75.0 cm` from end `A`. The diameter of unknown wire is 1 mm and length of the unknown wire is `31.4 cm`. Find the specific resistance of the unknown wire |
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Answer» `R/X=1/(100-l)` `rarr X=((100-l)/l)R` `=((100-75)/75) (300)=100Omega` Now, `X=(rhol)/A=(rhol)/((pid^2//4))` `rho=(pid^2X)/(4l)` `=((22//7)(10^-3)^2(100))/((4)(0.314))` `=2.5xx10^-4Omega-m` |
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