1.

if resistance of a wire formed by 1.cc of copper be 2.46 ohm. the diameter of wire is 0.32mm, then the specific resistance of wire eill be

Answer»

Hey mate!

as u know
R =RHO l/A

multiplying both NUMERATOR and denominator by A you will GET..

R =rho V/A^2

where,

V = volume (GIVEN 1cc)

A =area

rho =RA^2/V

1mm =0.1cm....

diameter=0.32mm =0.16 ×10^-cm..

Rho =2.46(0.16×0.16×10^-2 ×3.14)^2

rho =1.58 × 10^-6 ohm-cm



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