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If range of function f(x) = (2log_(2)^(1//4) x - 3log_(27)(x^(2)+1)^(2)-2x)/(7^(4)log_(49)x-x-1) is [a, infty], then 4a is equal to

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SOLUTION :`F(X) =(x^(4)-(x^(2)+1)-2x)/(x^(2)-x-1)=x^(2) + x+1`
`therefore f_("min ") = -B/(4A) = 3/4`
`therefore " range "=[3/4, INFTY] therefore a=3`


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