1.

If r the radius and a is th mass number of a necleus then the graph of log r versus log a will be

Answer»

#1 : We KNOW that Relation :
<klux>R</klux> = R_o A^{1/3} --(1)
where R = NUCLEAR Radius
R_o = 1.2 * 10^{-15} =1.2 fm
A = Mass Number

#2 : We have,
Taking log in both sides of EQUATION (1) :
log(R) = log(R_o) + \frac{1}{3} log(A) ----(1)

Hence, Graph of log(R) VS. log(A) will be a straight line whose :
Slope : 1/3
y- intercept = log(R_o)


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