If R is the range of a projectiel on a horizontal plane and h its maximum height, the maximum horizontal range with the same velocity ofprojection is:

If R is the range of a projectiel on a horizontal plane and h its maxi

1.	If R is the range of a projectiel on a horizontal plane and h its maximum height, the maximum horizontal range with the same velocity ofprojection is:
Answer» 2h `(R^(2))/(8h)` `2R+(h^(2))/(8R)` `2h+(R^(2))/(8h)` Solution :`2h+(R^(2))/(8h)=(2u^(2)SIN^(2)theta)/(2g)+(u^(4)sin^(2)theta//G^(2))/(8xxu^(2)sin ^(2)theta//2g)` `=(u^(2))/(g) sin^(2)theta+(u^(2))/(g) cos^(2)theta` `=(u^(2))/(g)=R_("max")`