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If R is the circum radius of `DeltaABC`, then A `(DeltaABC)`= . . .A. `(abc)/(R)`B. `(abc)/(4R)`C. `(abc)/(R)`D. `(abc)/(2R)` |
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Answer» Correct Answer - B In any `DeltaABC` we know that Area of `Delta = (1)/(2)` bc sin A `rArr " "sin A = (2Delta)/(bc)" "…….(i)` also `" "R=(a)/(2 sin A)" "……(ii)` From Eqs. (i) and (ii) , we have `R =(a)/(2((2Delta)/(bc)))` `rArr " "Delta = A(DeltaABC) =(abc)/(4R)` |
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