1.

If pressure at half the depth of a lake is equal to 2//3 pressure at the bottom of the lake then what is the depth of the lake ?A. 10 mB. 20 mC. 60 mD. 30 m

Answer» Correct Answer - B
(b) Pressure at bottom of the lake ` = P_0 + h rho g` and pressure at half the depth of a lake ` = P_0 + (h)/(2) rho g`
According to given condition
`P_0 + (1)/(2) h rho g = (2)/(3) (P_0 + h rho g) rArr (1)/(3) P_0 = (1)/(6)h rho g`
`rArr h = (2P_0)/(rhog) = (2xx 10^5)/(10^3 xx 10) = 20 m.`


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