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If pH of solution of NaOH is 12.0 the pH of H2 SO4 solution of same molarity will be?(a) 2.0(b) 12.0(c) 1.7(d) 10.0387 |
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Answer» Right answer is (c) 1.7 The best I can explain: pH = 12 then pOH = 2 [OH^–] = 10^-2 Molarity of NaOH = 10^-2 For H2 SO4, molarity = 10^-2 [H^+] = 2 × 10^-2 pH = 2 – log2 = 1.7. |
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